t=16t^2+96t+4

Solution for t=16t^2+96t+4 equation:

t=16t^2+96t+4

We move all terms to the left:

t-(16t^2+96t+4)=0

We get rid of parentheses

-16t^2+t-96t-4=0

We add all the numbers together, and all the variables

-16t^2-95t-4=0

a = -16; b = -95; c = -4;
Δ = b2-4ac
Δ = -952-4·(-16)·(-4)
Δ = 8769
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-95)-\sqrt{8769}}{2*-16}=\frac{95-\sqrt{8769}}{-32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-95)+\sqrt{8769}}{2*-16}=\frac{95+\sqrt{8769}}{-32}
$